Thursday, November 24, 2011

Escaping Java classpath wildcard on Windows command line!

I had a ridiculous battle with a set of .bat scripts that I wrote to launch java command line applications on Windows. I'm working on a suite of related little tools that I bundle into a zip file with a bunch of .jar files under a /lib/ folder, and launch scripts under a /bin/ folder that each look something like this:

@echo off

if not defined JAVACMD set JAVACMD=java.exe
if defined JAVA_HOME set JAVACMD="%JAVA_HOME%\bin\java.exe"

%JAVACMD% "-Djava.util.logging.config.file=%~dps0..\config\logging.properties" -cp "%~dps0..\lib\*" run.my.App %*

So I'm trying to use the nifty java classpath * wildcard introduced with java 6, but I had a terrible time with windows insisting on expanding /lib/* in the shell regardless of how I tried to quote or escape the thing! I was driving myself crazy, when I finally got the genious idea to just add a semicolon, so /lib/*; doesn't look like a path to Windows Powershell or CMD (I guess), and the following works:

@echo off

if not defined JAVACMD set JAVACMD=java.exe
if defined JAVA_HOME set JAVACMD="%JAVA_HOME%\bin\java.exe"

%JAVACMD% "-Djava.util.logging.config.file=%~dps0..\config\logging.properties" -cp "%~dps0..\lib\*;" run.my.App %*

What an amazingly stupid waste of time!

2 comments:

ankon said...

Thank you for this idea, I'm fighting with the same issue currently.

Could you tell me the version of java and windows you're using?

Unknown said...

Hi Ankon - I was using jdk6 at the time (don't know which sub-version) on Windows 7 - Good luck!